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Standard XII

Chemistry

Stoichiometric Calculations

AgCl with N...

Question

$A g C l$ with $N H_{3}$ forms a complex :

A g (N H_{3})_{2} C l

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A g N O_{3}

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A g N H_{2} C l

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A g

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Solution

The correct option is A $A g (N H_{3})_{2} C l$
$A g C l$ reacts with $N H_{3}$ to form a complex, $A g (N H_{3})_{2} C l$

$A g C l + 2 N H_{3} ⟶ [A g {(N H_{3})}_{2}] C l$

Option (A) is correct.

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Similar questions

{A g N O}_{3} + x H C l \to A g C l + {H N O}_{3} A g C l + {N H}_{y} O H \to [A g (N H_{3})_{2} C l] + {N H}_{4} C l

Find the value of x and y.

Q. What is the concentration of

A g^{+}

ion in

0.01 M A g N O_{3}

that is also

1.0 M N H_{3}

?
Will

A g C l

precipitate from a solution that is

0.01 M A g N O_{3}

0.01 M N a C l

and

1 M N H_{3}

?
Given : Formation constant,

K_{f} o f [A g (N H_{3})_{2}]^{+} = 1.70 \times 10^{7} a n d K_{s p} A g C l = 1.8 \times 10^{- 10}

Q. The correct order of the stoichiometries of

A g C l

formed when

A g N O_{3}

in excess is treated with the complexes:

C o C l_{3} .6 N H_{3}, C o C l_{3} .5 N H_{3}, C o C l_{3} .4 N H_{3}

respectively is:

Th correct order of the stochiometrics of AgCl formed when $A g N O_{3}$ in excess is treated with the complexes: $C o C l_{3} .6 N H_{3}, C o C l_{3} .5 N H_{3}, C o C l_{3} .4 N H_{3}$ respectively is

Q. One mole of the complex with molecular formula

[C o (N H_{3})_{5} C l_{3}]

gives two moles of

A g C l

with excess of

A g N O_{3}

. The complex is

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AgCl with NH3 forms a complex :

The correct option is A Ag(NH3)2ClAgCl reacts with NH3 to form a complex,Ag(NH3)2ClAgCl+2NH3⟶[Ag(NH3)2]ClOption (A) is correct.

$A g C l$ with $N H_{3}$ forms a complex :

The correct option is A $A g (N H_{3})_{2} C l$
$A g C l$ reacts with $N H_{3}$ to form a complex, $A g (N H_{3})_{2} C l$

$A g C l + 2 N H_{3} ⟶ [A g {(N H_{3})}_{2}] C l$

Option (A) is correct.