$A g N O_{3 (a q)} + H_{2} S_{(a q)} \to A g_{2} S_{(g)} + H N O_{3 (a q)}$
When the equation for the reaction represented above is balanced and all coefficient are reduced to lowest whole number terms, the coefficient for $A g N O_{3} (a q)$ is.

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Solution

The correct option is C 2
Rules for solving or balancing a chemical equation:-
1. Write an unbalanced equation.
2. Assign oxidation number for each atom.
3. Separate out reactions into two half reactions.
4. Balance all other atoms except $H$ and $O$ in each half reaction.
5. Balance the hydrogen by $H^{+}$ or $O H^{-}$ .
6. Balance the oxygen atoms by $H_{2} O$ .
7. Make electron gain equivalent to electron loss in the half reactions by multiplying them with respective numbers.
8. Add and simplify the half reactions together.
9. Check for elements and charges are balanced.

Balanced equation is
$2 A g N O_{3} + H_{2} S ⟶ A g_{2} S + 2 H N O_{3}$
as number of respective atoms on both sides are equal thus it is a balanced reaction.
Now, the co-efficient of $A g N O_{3}$ is $2$ .

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AgNO3(aq)+H2S(aq)→Ag2S(g)+HNO3(aq)When the equation for the reaction represented above is balanced and all coefficient are reduced to lowest whole number terms, the coefficient for AgNO3(aq) is.

$A g N O_{3 (a q)} + H_{2} S_{(a q)} \to A g_{2} S_{(g)} + H N O_{3 (a q)}$
When the equation for the reaction represented above is balanced and all coefficient are reduced to lowest whole number terms, the coefficient for $A g N O_{3} (a q)$ is.