$A g N O_{3} (a q)$ was added to an aqueous KCl solution gradually and the conductivity of the solution was measured. The plot of conductance (A) versus the volume of $A g N O_{3}$ is

(IIT-JEE, 2011)

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Solution

The correct option is D
S

$A g N O_{3} (a q) + K C l (a q) \to A g C l ↓ + K N O_{3} (a q)$
In this reaction, $C l^{⊖} i o n s a r e r e p l a c e d b y N O_{3}^{⊖}$ ions.

(i) Till all $K C l (C l^{⊖} i o n s)$ gets consumed by $N O_{3}^{⊖}$ ions, $C l^{⊖}$ will get replaced by $N O_{3}^{⊖}$ ion.
$K^{⨁} C l^{⊖} A g N O_{3} \to K^{⨁} N O_{3}^{⊖} .$
Conductance is constant since the conductance (A) of $C l^{⊖} \approx c o n d u c t a n c e o f N O_{3}^{⊖} .$
Initially, conductance do not fall to a large extent. Even the fall/rise will be linear (either decreasing or increasing).

(ii) When all $C l^{⊖}$ ions are reacted and no reaction occurs, there are $A g^{⨁}, N O_{3}^{⊖},$ and $K_{⨁}$ ions are left in the solution which increases the conductance of solution sharply.
$K^{⨁} C l^{⊖} A g N O_{3} \to A g^{⨁} + K^{⨁} + N O_{3}^{⊖}$

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