Question

\( \frac{ Br _{2}}{ FeBr _{3}} \) Majer product
(AIIMS 2018)

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

When 1-chloro-3-methylbenzene reacts with $B{r}_2/FeB{r}_3$, it produces 1-bromo-4-chloro-2-methylbenzene as a major product. +R effect of $Cl$ is dominated over hyperconjugation effect of methyl group so bromination occurs at ortho/para position.
$Br$ gets attached at para position due to steric hindrance at ortho position. The reaction for the same is given below.
\( \underset{ FeBr _{3}}{\stackrel{ Br _{2}}{\longrightarrow}} \)

Hence, option (b) is major product.