Air contains N2 and O2 in 4:1 ratio by volume. Approximate molecular weight of air (g/mole) is:
A
29
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B
38
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C
16
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D
74
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Solution
The correct option is A29 The molecular weight of air = mole fraction of nitrogen × molecular weight of nitrogen + mole fraction of oxygen × molecular weight of oxygen.
Now, mole fraction of nitrogen =45=0.80 and mole fraction of oxygen =15=0.20.
So, molecular weight of air =0.8×28+0.2×32=29 g/mole.