Air contains nitrogen and oxygen in the volume ratio of $4 : 1$ The average vapour density of air is :

30

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28.8

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28

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14.4

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Solution

The correct option is D $14.4$
$V a p o u r d e n s i t y = a v e r a g e r e l a t i v e d e n s i t y$
Molar mass $= 2 \times (V a p o o u r d e n s i t y) . . (i)$
Given, $O_{2} = 20$ %,
$N_{2} = 80$ %
Average molar mass of air $= \frac{20 \times 32 + 80 \times 28}{100} = 28.8 g m$
Using equation $(i)$ ,
$28.8 = 2 \times V a p o u r d e n s i t y$
Vapour density $= 14.4$

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