Air distance between Kota to Jaipur is $260 k m$ and road distance is $320 k m$ . A deluxe but which is from Jaipur to Kota reach in $8 h$ while an aeroplane reach in just $15 m i n$ .
(i) Average speed of bus in $k m / h$
(ii) Average velocity of bus in $k m / h$
(iii) Average speed of aeroplane in $k m / h$
(iv) Average velocity of aeroplane in $k m / h$

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Solution

(1) Average speed of Bus = $\frac{d i s t a n c e}{t i m e} = 320 / 8 = 40 K m / h$
(2)Average velocity of bus $= \frac{D i s p l a c e m e n t}{t i m e} = Air distance(Shortest) / 8 = 260 / 8 = 32.5 K m / h$
(3)Average speed of aeroplane= $diatance travelled by it / t i m e = 260 / (0.25) = 1040 K m / h$
(4) Average velocity of Aeroplane $= D i s p a l c e m e n t / t i m e = 260 / (0.25) = 1040 K m / h$

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(1) Average speed of Bus =distancetime=320/8=40Km/h(2)Average velocity of bus=Displacementtime=Air distance(Shortest)/8=260/8=32.5Km/h(3)Average speed of aeroplane=diatance travelled by it/time=260/(0.25)=1040Km/h(4) Average velocity of Aeroplane=Dispalcement/time=260/(0.25)=1040Km/h