Air is streaming past a horizontal air plane wing such that its speed is 120m/s over the upper surface and 90 m/s at the lower surface. If the density of air is 1.3 kg per $m e t r e^{3}$ and the wing is 10 m long and has an average width of 2 m, then the difference of the pressure on the two sides of the wing is

4095.0 Pascal

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409.50 Pascal

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40.950 Pascal

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4.0950 Pascal

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Solution

The correct option is A
4095.0 Pascal

From the Bernoulli's theorem

$P_{1} - P_{2} = \frac{1}{2} ρ (v_{2}^{2} - v_{1}^{2}) = \frac{1}{2} \times 1.3 \times [(120)^{2} - (90)^{2}]$

$= 4095 N / m^{2}$ or Pascal

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Similar questions

Q. Air is streaming past a horizontal air plane wing such that its speed in 120 m/s over the upper surface and 90 m/s at the lower surface. If the density of air is 1.3 kg per

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Air is streaming past a horizontal airplane wing such that its speed is $120$ over the upper surface and $90 m / s$ at the lower surface. If the density of air is $1.3 k g / m^{3}$ and the wing is 10 m long and has an average width of 2 m, then the difference of the pressure on the two sides of the wing of

Q. Air is streaming past a horizontal airplane wing such that its speed is

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= 1.3 k g m^{- 3})

Air is streaming past a horizontal airplane wing such that its speed is 120 m/s over the upper surface and 90 m/s at the lower surface. If the density of the air is 1.3 kg/m³ and the wing is 10 m long and has an average width of 2 m, then the difference of pressure on the two sides of the wing is

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The correct option is A 4095.0 Pascal From the Bernoulli's theorem P1−P2=12ρ(v22−v21)=12×1.3×[(120)2−(90)2] =4095 N/m2 or Pascal

The correct option is A
4095.0 Pascal

From the Bernoulli's theorem

$P_{1} - P_{2} = \frac{1}{2} ρ (v_{2}^{2} - v_{1}^{2}) = \frac{1}{2} \times 1.3 \times [(120)^{2} - (90)^{2}]$

$= 4095 N / m^{2}$ or Pascal