Air us pumped into an automobile tube upto a pressure of 200kPa in the morning when the air temperature is $22^{0} C$ . During the day, temperature rises to $42^{0} C$ and the tube expands by 2%. The pressure of he air in the tube at this temperature, will be approximately

212kPa

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209kPa

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206kPa

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200kPa

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Solution

The correct option is A 209kPa
Let the initial volume be $V_{1} = V$
final volume $V_{f} = 1.02 V$
$T_{1} = 295 K, P_{1} = 200 k P$
$T_{2} = 315 K$
Using, $P_{1} V_{1} / T_{1} = P_{2} V_{2} / T_{2} \Rightarrow P_{2} = 209.37 k P a$

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Similar questions

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Air us pumped into an automobile tube upto a pressure of 200kPa in the morning when the air temperature is 220C. During the day, temperature rises to 420C and the tube expands by 2%. The pressure of he air in the tube at this temperature, will be approximately

The correct option is A 209kPaLet the initial volume be V1=Vfinal volume Vf=1.02VT1=295K,P1=200kPT2=315KUsing, P1V1/T1=P2V2/T2⇒P2=209.37kPa

Air us pumped into an automobile tube upto a pressure of 200kPa in the morning when the air temperature is $22^{0} C$ . During the day, temperature rises to $42^{0} C$ and the tube expands by 2%. The pressure of he air in the tube at this temperature, will be approximately

The correct option is A 209kPa
Let the initial volume be $V_{1} = V$
final volume $V_{f} = 1.02 V$
$T_{1} = 295 K, P_{1} = 200 k P$
$T_{2} = 315 K$
Using, $P_{1} V_{1} / T_{1} = P_{2} V_{2} / T_{2} \Rightarrow P_{2} = 209.37 k P a$