Ajit carries a load of 17 kg from the ground on his head and takes it to the heights of 2 m from the ground. Calculate the work done by him.

34 J

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17 J

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0 J

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333.2 J

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Solution

The correct option is C 333.2 J
Work done $= F . s = m g S$
Load $= 17 k g$
Acceleration $= 9.8 m / s^{2}$
Height $= 2 m$
Work $= m g S = 17 \times 9.8 \times 2 = 333.2 J$

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Ajit carries a load of 17 kg from the ground on his head and takes it to the heights of 2 m from the ground. Calculate the work done by him.

The correct option is C 333.2 JWork done =F.s=mgSLoad =17kgAcceleration =9.8m/s2Height =2mWork =mgS=17×9.8×2=333.2J

The correct option is C 333.2 J
Work done $= F . s = m g S$
Load $= 17 k g$
Acceleration $= 9.8 m / s^{2}$
Height $= 2 m$
Work $= m g S = 17 \times 9.8 \times 2 = 333.2 J$