Akash has 6xy+4x $y^{2}$ chocolates. He wants to distribute them to 2x children. How many chocolates does each of the child get if y=2?

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Solution

2x children will get $6 x y + 4 x y^{2}$ chocolates.

So, 1 child will get $\frac{6 x y + 4 x (y^{2})}{2 x}$ chocolates.

Factorize $6 x y + 4 x y^{2}$ by using method of common factors.

$2 \times 3 \times x \times y + 2 \times 2 \times x \times y \times y = 2 x (3 y + 2 y^{2})$

So, $\frac{6 x y + 4 x (y^{2})}{2 x}$ = $\frac{2 x (3 y + 2 y^{2})}{2 x} = (3 y + 2 y^{2})$

Given y=2. So, substitute in $(3 y + 2 y^{2})$

$3 \times 2 + 2 \times 2 \times 2 = 6 + 8 = 14$

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