Akash has $6 x y + 4 x y^{2}$ chocolates. He wants to distribute them to 2x children. How many chocolates does each child get if y = 2?
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Solution

$2 x$ children will get $6 x y + 4 x y^{2}$ chocolates.
So, 1 child will get $\frac{6 x y + 4 x (y^{2})}{2 x}$ chocolates.

So $\frac{6 x y + 4 x (y^{2})}{2 x}$ = $\frac{6 x y}{2 x} + \frac{4 x (y^{2})}{2 x}$ = $(3 y + 2 y^{2}$ )

Given y = 2. Substituting the value of y in $(3 y + 2 y^{2}$ )

$3 \times 2 + 2 \times 2 \times 2 = 6 + 8 = 14$

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