Akshatha walks 10 m facing the early morning Sun and goes 10 m to the right. She then walks 5, 15 and 15 m, each time turning to her left. How far is she now from her starting point(in m)?
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Solution
A is the starting point G is the final point. DF=15m DE=CB=10m EF=DF−DE=15−10=5m AG=EF=5m. Hence, Akshatha is 5 m from the starting point.