Akshay spins a spinner that is split into 10 equals sections The sections are labelled 1, 3, 2, 1, 2, 2, 3, 1, 2, 1 What is the probability that the spinner will land on the number 2

\frac{1}{10}

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\frac{2}{5}

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\frac{1}{2}

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\frac{1}{5}

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Solution

The correct option is B $\frac{2}{5}$
The number of sections labelled '2' = 4
Total number of sections = 10
$∴$ P(number 2) = $\frac{4}{10} = \frac{2}{5}$

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Akshay spins a spinner that is split into 10 equals sections The sections are labelled 1, 3, 2, 1, 2, 2, 3, 1, 2, 1 What is the probability that the spinner will land on the number 2

The correct option is B 25The number of sections labelled '2' = 4Total number of sections = 10∴ P(number 2) = 410=25

The correct option is B $\frac{2}{5}$
The number of sections labelled '2' = 4
Total number of sections = 10
$∴$ P(number 2) = $\frac{4}{10} = \frac{2}{5}$