The correct options are
A soluble in NaOH
B a white coloured compound
C insoluble in excess of NH4OH
Al2(SO4)3+6NH4OH→2Al(OH)3+3(NH4)2SO4
X is Al(OH)3 which is white gelatinous precpitate soluble in strong alkalis like NaOH and insoluble in excess of NH4OH.
Al(OH)3+NaOH→Na[Al(OH)4]