$A l_{2} (S O_{4})_{3} . x H_{2} O$ has $8.20$ % $A l$ by mass. The value of $x / 3$ is _________.

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Solution

According to given conditions for $A l_{2} (S O_{4})_{3} . x H_{2} O$ ,

$\frac{54 \times 100}{(18 x + 3 \times 96 + 54)} = 8.20$
$∴ x \approx 18$ .

$∴ \frac{x}{3} = \frac{18}{3} = 6$

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