Al and KClO3 react together to form AI2O3 according to the following reaction: 2KClO3⟶2KCl+3O2 4Al+3O2⟶2Al2O3 4 moles of KClO3 (50% pure) on reaction with excess of Al forms Al2O3 equal to :
A
2 mol
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B
4 mol
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C
6 mol
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D
8 mol
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Solution
The correct option is A2 mol The reactions are as follows: 2KClO3⟶2KCl+3O2 4Al+3O2⟶2Al2O3 50% of 4 moles of 2KClO3 means 2 moles. According to the balanced reaction, 2 moles of KClO3 forms 2 moles of Al2O3.