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Question

Al and KClO3 react together to form AI2O3 according to the following reaction:
2KClO32KCl+3O2
4Al+3O22Al2O3
4 moles of KClO3 (50% pure) on reaction with excess of Al forms Al2O3 equal to :

A
2 mol
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B
4 mol
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C
6 mol
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D
8 mol
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