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Redox Reactions

Al + MnO4- → ...

Question

$A l + M n O_{4}^{-} \to A l (O H)_{4}^{-} + M n O_{2}$
For this reaction, element $X$ is reduced and element Y is oxidised. Then $X$ and $Y$ are respectively:

A

A l a n d M n

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B

M n a n d A l

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C

A l a n d A l

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D

M n a n d M n

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Solution

The correct option is C $M n a n d A l$
In the reaction the $A l$ is changing to ${A l (O H)_{4}}^{-}$ . Its oxidation state is changing from $0$ to $+ 3$ . Increase in oxidation state indicates the element is oxidized,
And ${M n O_{4}}^{-}$ is converting to $M n O_{2}$ . Its oxidation state is changing from $+ 7$ to $+ 4$ . A decrease in oxidation state indicates the element is reduced.
Thus for this reaction, the element $X$ is $M n$ which is reduced and the element $Y$ is $A l$ which is oxidized.

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A l + M n O_{4}^{-} \to A l (O H)_{4}^{-} + M n O_{2}

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A l + M n O_{4}^{-} \to A l (O H)_{4}^{-} + M n O_{2}

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