$A l (O H)_{3} + H_{2} S O_{4} \to A l_{2} (S O_{4})_{3} + H_{2} O$
After balancing the reaction, what would be the coefficients of all the reactants and products?

1, 3, 1, 2

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2, 3, 2, 6

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2, 3, 1, 6

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2, 6, 1, 3

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1, 3, 1, 6

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Solution

The correct option is C $2, 3, 1, 6$
The unbalanced chemical equation is $A l (O H)_{3} + H_{2} S O_{4} \to A l_{2} (S O_{4})_{3} + H_{2} O$ .
Balance Al atoms.
$2 A l (O H)_{3} + H_{2} S O_{4} \to A l_{2} (S O_{4})_{3} + H_{2} O$
Balance S atoms.
$2 A l (O H)_{3} + 3 H_{2} S O_{4} \to A l_{2} (S O_{4})_{3} + H_{2} O$
Balance H atoms.
$2 A l (O H)_{3} + 3 H_{2} S O_{4} \to A l_{2} (S O_{4})_{3} + 6 H_{2} O$
O atoms are already balanced. This is balanced chemical equation.
The coefficients of all the reactants and products are $2, 3, 1, 6$
Hence, the option (C) is the answer.

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