$A l (s) + O_{2} (g) \to A l_{2} O_{3} (s)$
The above reaction is balanced so that its coefficients are the lowest whole-number. Find the coefficient of $O_{2}$ .

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Solution

The correct option is D 3
The unbalanced chemical reaction is $A l (s) + O_{2} (g) \to A l_{2} O_{3} (s)$
Balance $A l$ atoms by adding 2 to $A l$ on LHS
$2 A l (s) + O_{2} (g) \to A l_{2} O_{3} (s)$
Balance $O$ atoms by adding $\frac{3}{2}$ to $O_{2}$ on LHS
$2 A l (s) + \frac{3}{2} O_{2} (g) \to A l_{2} O_{3} (s)$
Multiply the whole equation with 2.
$4 A l (s) + 3 O_{2} (g) \to 2 A l_{2} O_{3} (s)$
This is the balanced chemical equation. The coefficient of $O_{2}$ is 3.

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