Question

Alan has a box containing 8 blue, 6 red, and 4 green balls in it. If one ball is taken out at random, what is the probability of it being red?
(Note: Assume all the outcomes are equally likely.)

• A. $\frac{7}{13}$
• B. $\frac{2}{9}$
• C. $\frac{1}{3}$
• D. $\frac{6}{13}$

Answer 1

The correct option is C $\frac{1}{3}$

Number of red balls $=6$
Total number balls (blue + red + green) $=8+6+4=18$
So, the probability of a ball chosen at random being red $=\frac{\text{Number of red balls}}{\text{Total number of balls}}=\frac{6}{18}=\frac{1}{3}$