Albinism in human is controlled by a recessive gene 'a'. If both parents were known to be carriers (Aa) for albinism, what are the chances of 1 normal and 3 albinoes in a family of four?
A
12/256
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B
81/256
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C
108/256
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D
54/256
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E
1/256
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Solution
The correct option is B 12/256 Parent 1 will have Aa and second parent will have Aa genotype when there are crossed offsprings produced will be AA, Aa, Aa, aa, the chances of affected offspring is 25% rest 75% will be normal. Probability will be (1/4 x 3/4 x (1/4)^3)= 12/256.