Aldol condensation reaction is not given by:

C_{6} H_{5} C H_{2} C H O

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C_{6} H_{5} C H O

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C H_{3} C H O

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C H_{3} C O C H_{3}

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Solution

The correct option is A $C_{6} H_{5} C H O$
$C_{6} H_{5} C H O$ has no $H$ and $α -$ carbon. Thus, no aldol condensation.

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C_{6} H_{5} C H O + C H_{3} C H O \to C_{6} H_{5} C H = C H - C H O

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