Question

Alex ate $\frac{3}{4}th$ of the cheese pizza, $\frac{6}{8}th$ of the onion pizza, and $\frac{11}{16}th$ of the tomato pizza. From which plate did he eat the maximum amount of pizza?

Answer 1

Alex ate $\frac{3}{4}th$ of the first pizza, $\frac{6}{8}th$ of the second pizza and $\frac{11}{16}th$ of the third pizza.
Now, let’s compare the fractions by making the denominator the same.

Here, we make the same denominator, let’s multiply by 4, 2 and 1 with $\frac{3}{4}$ , $\frac{6}{8}$ and $\frac{11}{16}$, respectively.

$\frac{3\times 4}{4\times 4}=\frac{12}{16}$
$\frac{6\times 2}{8\times 2}=\frac{12}{16}$
$\frac{11\times 1}{16\times 1}=\frac{11}{16}$

Now, comparing the fractions with the same denominators, we have $\frac{12}{16}$ in the cheese and onion pizza and $\frac{11}{16}$ in the third pizza.
So, the maximum is $\frac{12}{16}$ as it is greater than $\frac{11}{16}$.

The maximum amount eaten is from the cheese and onion pizza.