3
Question
Alex is 10 cm shorter than Amay. Amay’s father is 190 cm tall and is twice as tall as Amay. What is the height of Alex?
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Solution
Height of Amay’s father = 190 cm
The height of Amay's father is twice the height of Amay.
So, Amay’s height will be half of his father = 190 ÷ 2 = 95 cm
Given that Alex is 10 cm shorter than Amay.
So, Alex’s height = 95 - 10 = 85 cm
The height of Amay's father is twice the height of Amay.
So, Amay’s height will be half of his father = 190 ÷ 2 = 95 cm
Given that Alex is 10 cm shorter than Amay.
So, Alex’s height = 95 - 10 = 85 cm
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