Alex took a $6$ -mile walk to his friend’s house. He left at $9$ a.m. and arrived at his friend’s house at $11$ a.m. If the return trip took one hour longer, how much slower was his speed on the return trip than on the trip to his friend’s house?

3

miles per hour

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1

mile per hour

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2.5

miles per hour

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2

miles per hour

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Solution

The correct option is B $1$ mile per hour
Total distance walked $= 6$ miles
Time taken by Alex to go to his friend’s house $= 2$ hours
Speed of Alex $= \frac{6}{2} = 3$ miles per hour
Time taken while returning $= 3$ hours
Speed of Alex during the return trip $= \frac{6}{3} = 2$ miles per hour
Therefore, his speed was reduced by $1$ mile per hour on the return trip.

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Alex took a 6-mile walk to his friend’s house. He left at 9 a.m. and arrived at his friend’s house at 11 a.m. If the return trip took one hour longer, how much slower was his speed on the return trip than on the trip to his friend’s house?

Alex took a $6$ -mile walk to his friend’s house. He left at $9$ a.m. and arrived at his friend’s house at $11$ a.m. If the return trip took one hour longer, how much slower was his speed on the return trip than on the trip to his friend’s house?