Question

Algebraic sum of the intercepts made by the plane x + 3y – 4z + 6 = 0 on the axes is :

• A. $\frac{-13}{2}$
• B. $\frac{-19}{2}$
• C. $\frac{-22}{3}$
• D. $\frac{13}{2}$

Answer 1

The correct option is A $\frac{-13}{2}$

x + 3y – 4z + 6 = 0
$\Rightarrow \frac{x}{-6}+\frac{y}{-2}+\frac{z}{\frac{3}{2}}=1soa+b+c=\frac{-13}{2}$