Question

Algebraic sum of the intercepts made by the plane x + 3y - 4z + 6 = 0 on the axes is

• A. $-\frac{13}{2}$
• B. $\frac{19}{2}$
• C. $-\frac{22}{3}$
• D. $-\frac{26}{3}$

Answer 1

The correct option is A $-\frac{13}{2}$

Equation of the plane can be written as $\frac{x}{-6}+\frac{y}{-2}+\frac{z}{\frac{3}{2}}=1$
So the intercepts on the coordinates axes are $-6,-2,\frac{3}{2}$ and the required sum is
$-6-2+\frac{3}{2}=-\frac{13}{2}$.