Alkane can be iodinated in the presence of:

H I

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I_{2}

and

P

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H I O_{3}

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P I_{3}

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Solution

The correct option is C $H I O_{3}$
Iodination of an alkane is carried out in the presence of oxidizing agent because one of the products of this reaction is hydrogen iodide and this is a strong reducing agent and converts alkyl iodide back to an alkane.

Therefore to counter this difficulty, the iodination of alkanes are carried out in the presence of a strong oxidizing agent like iodic acid $(H I O_{3})$ which oxidizes the hydrogen iodide formed.

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Similar questions

H I O_{3}

H N O_{3}

H N O_{3}

H I O_{3}

I_{2}

P I_{3}

O H

R - I

2 P + 3 I \to 2 P I_{3}

3 R O H + P I_{3} \to 3 R I + H_{3} P O_{3}

In the Iodination of alkane, Some HIO₃ is added so that :

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