Alkyl halides can be obtained by all methods except :

{C H}_{3} {C H}_{2} O H + H C l (g) Z n {C l}_{2} ⟶

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{C H}_{3} - C H = {C H}_{2} S O_{2} {C l}_{2}, 475 K ⟶

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C_{2} H_{5} O H + N a C l \to

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{C H}_{3} C O O A g + {B r}_{2} C {C l}_{4}, R e f l u x ⟶

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Solution

The correct option is C $C_{2} H_{5} O H + N a C l \to$
Alkyl halides can be obtained by the following methods.
(A) Groove's method in which an alcohol reacts with HX in presence of anhydrous zinc chloride.
$C H_{3} C H_{2} O H + H X a n h y d - --- \to Z n C l_{2} C H_{3} C H_{2} C l + H_{2} O$ .

(B) By the reaction of an alkane / alkene with thionyl chloride.
$C H_{2} = C H - C H_{3} S O_{C} l_{2} - --- \to K C H_{2} = C H - C H_{2} - C l + S O_{2} + H C l$ .

(D) By Borodine-Hunsdiecker reaction.
$C H_{3} C O O A g + B r_{2} / C C l_{4} \to C H_{3} B r + C O_{2} + A g B r$
However the alkyl halide cannot be prepared by the reaction of alkene with NaCl.

$C_{2} H_{4} + N a C l \to N o r e a c t i o n$

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