Alkyl halides reactivity order in unimolecular elimination reactions $(E_{1})$ is:

1^{o} > 2^{o} > 3^{o}

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2^{o} > 1^{o} > 3^{o}

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1^{o} < 2^{o} < 3^{o}

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2^{o} < 1^{o} < 3^{o}

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Solution

The correct option is C $1^{o} < 2^{o} < 3^{o}$
The correct order will be- $3^{0} > 2^{0} > 1^{0}$ . E1 This is due to the stability of carbocation phenomena of hyperconjugation, which allows a nearby C-C or C-H bond to interact with the p orbital of the carbon to bring the electrons down to a lower energy state.

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