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Byju's Answer
Standard XII
Chemistry
Polyhalogen Compounds
Alkyl iodides...
Question
Alkyl iodides can be prepared by:-
A
R
C
H
2
C
O
O
A
g
+
I
2
C
C
l
4
⟶
Δ
R
C
H
2
I
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B
R
C
H
2
C
l
+
N
a
I
a
c
e
t
o
n
e
⟶
Δ
R
C
H
2
I
+
N
a
C
l
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C
R
−
O
H
+
H
I
⟶
R
I
+
H
2
O
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D
C
H
4
+
I
2
⟶
C
H
3
I
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Solution
The correct options are
B
R
−
O
H
+
H
I
⟶
R
I
+
H
2
O
C
R
C
H
2
C
l
+
N
a
I
a
c
e
t
o
n
e
⟶
Δ
R
C
H
2
I
+
N
a
C
l
Alkyl halides are prepared by following reactions:
Finkelstein reaction or halogen exchange reaction:
R
C
H
2
C
l
+
N
a
I
a
c
e
t
o
n
e
⟶
Δ
R
C
H
2
I
+
N
a
C
l
R
−
O
H
+
H
I
⟶
R
I
+
H
2
O
Requires presence of sulphuric acid.
The reaction
C
H
4
+
I
2
⟶
C
H
3
I
is reversible and must be carried out in presence of oxidizing agents such as
H
I
O
3
,
H
N
O
3
or
H
I
O
4
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0
Similar questions
Q.
Alkyl iodides are often prepared by the reaction of alkyl chlorides/ bromides with
N
a
I
in dry acetone. This reaction is known as
Q.
C
H
4
can be prepared by the reaction of
H
2
O
with:
Q.
The rate of decomposition of aldehyde
(
C
H
3
C
H
O
)
into
C
H
4
and
C
O
in presence of
I
2
at 800 K follows the rate law:
r
=
K
[
C
H
3
C
H
O
]
[
I
2
]
. The decomposition is believed to go to the two step mechanism:
C
H
3
C
H
O
+
I
2
→
C
H
3
I
+
H
I
+
C
O
C
H
3
I
+
H
I
→
C
H
4
+
I
2
What is the catalyst for the reaction? Which of the two steps is the slower one?
Q.
Why is acetone the best solvent for the reaction between alkyl chloride and potassium iodide?
Q.
Alkene can be prepared from alkyl halide by the following reagent
R
−
X
+
N
¯
u
→
A
l
k
e
n
e
+
N
u
H
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