Alkynes on reduction with sodium in liquid ammonia form trans alkenes. Will the butene thus formed on reduction of 2-butyne show the geometrical isomerism?
Alkynes on reduction with sodium in liquid ammonia forms trans alkenes.
Thus, on reduction of 2-butyne, the product formed will be but-2-ene.
For a molecule to show geometrical isomerism, two unlike atoms or groups must be linked to each doubly bonded carbon atom. Thus, geometrical isomerism is possible when both substituents at each carbon are different.
Now, in 2-butene one hydrogen atom and one methyl group are linked to each double bonded carbon atoms and since both the carbons have different substituents group thus 2-butene will show geometrical isomerism.
Also, when 2 methyl groups lies on opposite sides of the double bond, thus the isomer is called as trans-isomer, while when they lies on same side, it is called as cis-isomer.
Alkynes on reduction with sodium in liquid ammonia forms trans alkenes.
Thus, on reduction of 2-butyne, the product formed will be but-2-ene.
For a molecule to show geometrical isomerism, two unlike atoms or groups must be linked to each doubly bonded carbon atom. Thus, geometrical isomerism is possible when both substituents at each carbon are different.
Now, in 2-butene one hydrogen atom and one methyl group are linked to each double bonded carbon atoms and since both the carbons have different substituents group thus 2-butene will show geometrical isomerism.
Also, when 2 methyl groups lies on opposite sides of the double bond, thus the isomer is called as trans-isomer, while when they lies on same side, it is called as cis-isomer.
