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AC Applied to a Resistor

All capacitor...

Question

All capacitors were initially uncharged. Battery current just after closing the switch is

A

1A

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B

2A

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C

3A

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D

4A

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Solution

The correct option is D 4A
Capacitors behave as short circuit, just after closing the switch.
Resistors in bridge become parallel.

Net resistance of circuit is Reff = $10 Ω + (10 ∥ 5 ∥ 10) = 12.5 Ω$

Current through battery, $i = \frac{50}{12.5} = 4 A$

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