The correct option is A (1, −2)
Let the equation of chord by y = mx + c. Combined equation of line joining the point intersection with origin is
3x2−y2−2(x−2y)(y−mxc)=0i.e.,x2(3c+2m)−y2(c−4)−2xy(1+2m)=0
These lines will be mutually perpendicular, if
3c + 2m – c + 4 = 0
⇒ 2m + 2c = −4
⇒ m + c = −2
That means the chord y = mx + c is always pass through the point (1, −2).
Hence, (a) is the correct answer.