All electron ejected from a surface by incident light of wavelength 200 nm can be stopped before travelling 1 m in the direction of uniform electric field of 4N/C. The work function of the surface is

4eV

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6.2eV

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2eV

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2.2eV

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Solution

The correct option is B 2.2eV
The electron ejected with maximum speed $v_{m a x}$ are stopped by electric field E after travelling distance d
Work done by electric field = $F o r c e \times d i s t a n c e = E e d$
Photolelectric Law
$K E_{m a x} = \frac{h c}{λ} - W_{o}$
$E_{e d} =$ $\frac{h c}{λ} - W$
$4 e V = \frac{1240}{200} - W_{o}$
$W_{o} = 6.2 - 4 = 2.2 e V$

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All electron ejected from a surface by incident light of wavelength 200 nm can be stopped before travelling 1 m in the direction of uniform electric field of 4N/C. The work function of the surface is

The correct option is B 2.2eVThe electron ejected with maximum speed vmax are stopped by electric field E after travelling distance dWork done by electric field =Force×distance=EedPhotolelectric LawKEmax=hcλ−WoEed= hcλ−W4eV=1240200−WoWo=6.2−4=2.2eV