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Question

# All five faces of a regular pyramid with a square base are found to be of the same area. The height of the pyramid is 3 cm. What is the minimum total area (integral) of all its surfaces?

A
102 sq cm
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B
122 sq cm
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C
152 sq cm
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D
202 sq cm
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Solution

## The correct option is B 122 sq cmAltitude of the traingular faces = √a24+9 Area of faces =2 x a x √a24+9 The total surface area = area of base + lateral surface area = a2 + 2 x a x √a24+9 Lets us put a=8 (smallest value whch will yield an integer area, Area = 64 + 2 × 8 × 5 =144) = 122

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