Question

'All hybrid orbitals have equal energy level.' Which of the following hybridization does not comply with above statement?

• A. $s{p}^2$
• B. $s{p}^3{d}^2$
• C. $s{p}^3$
• D. $s{p}^{3}d$

Answer 1

The correct option is D $s{p}^{3}d$

(A) (Refer to Image 1)

(B) (Refer to Image 2)

(C) (Refer to Image 3)

(D) (Refer to Image 4)

Only $s{p}^{3}d$ hybridizationdoes not comply the given statement because $s{p}^{3}d$ hybridization is made by combination of $s{p}^2$ hybridization and $d_{z^2}{P}_z$ hybridization. As a result all hybridised are not having equal shape or equal energy. But other hybridizations $s{p}^2,s{p}^3$ and $s{p}^3{d}^2$ have equal energy level.