All possible values of eccentric angle of x 1- y 1 on x 2-6- y 2-2-1 whose distance fromt the centre is 2 -A- - 45B- 45C- 90D- -45

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Eccentric Angle : Hyperbola

All possible ...

Question

All possible values of eccentric angle of $(x_{1}, y_{1})$ on $\frac{x^{2}}{6} + \frac{y^{2}}{2} = 1$ whose distance fromt the centre is 2.

\pm

45.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-45

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\pm$ 45.
Let the ecentric angle be t, and $a^{2} = 6; b^{2} = 2$
$x_{1} = a c o s t$ $y_{1} = b s i n t$
$(a c o s t)^{2} + (b s i n t)^{2} = 4$
t = $\pm$ 45.

Suggest Corrections

Similar questions

Q. All possible values of eccentric angle of

(x_{1}, y_{1})

\frac{x^{2}}{6} + \frac{y^{2}}{2} = 1

whose distance fromt the centre is 2.

Find the eccentric angle of a point on the ellipse $\frac{x^{2}}{6} + \frac{y^{2}}{2} = 1$ whose distance from centre is 2.

Q. The eccentric angle of a point on the ellipse

\frac{x^{2}}{6} + \frac{y^{2}}{2} = 1

whose distance from the centre of ellipse is

2

, is:

The eccentric angle $θ$ of a point $(\sqrt{6} cos θ, \sqrt{2} sin θ)$ on the ellipse $\frac{x^{2}}{6} + \frac{y^{2}}{2} = 1$ whose distance from the centre of the ellipse is $2$ is

Q. The eccentric angle of a point on the ellipse

\frac{x^{2}}{6} + \frac{y^{2}}{2} = 1

whose distance from the centre of the ellipse is

\sqrt{5},

units is/are

Join BYJU'S Learning Program

All possible values of eccentric angle of (x1,y1) on x26+y22=1 whose distance fromt the centre is 2.

The correct option is A ± 45.Let the ecentric angle be t, and a2=6;b2=2 x1=a cos t y1=b sin t (a cos t)2+(b sin t)2=4 t = ± 45.

All possible values of eccentric angle of $(x_{1}, y_{1})$ on $\frac{x^{2}}{6} + \frac{y^{2}}{2} = 1$ whose distance fromt the centre is 2.

The correct option is A $\pm$ 45.
Let the ecentric angle be t, and $a^{2} = 6; b^{2} = 2$
$x_{1} = a c o s t$ $y_{1} = b s i n t$
$(a c o s t)^{2} + (b s i n t)^{2} = 4$
t = $\pm$ 45.