Question

All resistors in the circuit have the same resistance, $R$, and the battery is having a constant voltage $V$.
Find out the relation between current through the resistor a and b.

• A. The current through Resistor $a$ is $9$ times the current through Resistor $b$
• B. The current through Resistor $a$ is $3$ times the current through Resistor $b$
• C. The current through Resistor $a$ is the same as the current through Resistor $b$
• D. The current through Resistor $b$ is $3$ times the current through Resistor $a$
• E. The current through Resistor $b$ is $9$ times the current through Resistor $a$

Answer 1

Answer: (B)

The current through Resistor $a$ is $3$ times the current through Resistor $b$

Since the resistances $a,e,f$ and combination of $b,c,d$ are in series with each other, the current through them is same.

The same current gets divided equally in the three resistances $b,c,d$, thus current in $a$ is three times that in $b$.