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Byju's Answer

Standard XII

Physics

Limiting Friction

All surfaces ...

Question

All surfaces assumed to be frictionless. Calculate the horizontal force $F$ that must be applied so that $m_{1}$ and $m_{2}$ do not move relative to $m_{3}$ is:-

(m_{1} + m_{2} + m_{3}) \frac{m_{2} g}{m_{1}}

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(m_{1} + m_{2}) \frac{m_{2} g}{m_{1}}

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(m_{2} + m_{3}) \frac{m_{1} g}{m_{2}}

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(m_{1} + m_{3}) \frac{m_{1} g}{m_{2}}

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Solution

The correct option is D $(m_{1} + m_{2} + m_{3}) \frac{m_{2} g}{m_{1}}$
$a = \frac{F}{m_{1} + m_{2} + m_{3}}$
$T = m_{1} a$
$T = m_{2} g$
for equilibrium
$m_{1} a = m_{2} g$ or $a = \frac{m_{2}}{m_{1}} g$
$F = (m_{1} + m_{2} + m_{3}) a$
$∴ F = (m_{1} + m_{2} + m_{3}) \frac{m_{2}}{m_{1}} g$

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All surfaces assumed to be frictionless. Calculate the horizontal force F that must be applied so that m1 and m2 do not move relative to m3 is:-

The correct option is D (m1+m2+m3)m2gm1a=Fm1+m2+m3T=m1aT=m2gfor equilibriumm1a=m2g or a=m2m1gF=(m1+m2+m3)a∴F=(m1+m2+m3)m2m1g

All surfaces assumed to be frictionless. Calculate the horizontal force $F$ that must be applied so that $m_{1}$ and $m_{2}$ do not move relative to $m_{3}$ is:-

The correct option is D $(m_{1} + m_{2} + m_{3}) \frac{m_{2} g}{m_{1}}$
$a = \frac{F}{m_{1} + m_{2} + m_{3}}$
$T = m_{1} a$
$T = m_{2} g$
for equilibrium
$m_{1} a = m_{2} g$ or $a = \frac{m_{2}}{m_{1}} g$
$F = (m_{1} + m_{2} + m_{3}) a$
$∴ F = (m_{1} + m_{2} + m_{3}) \frac{m_{2}}{m_{1}} g$