All the energy released from the reaction X→Y,△rG∘=−193kJmol−1 is used for oxidising M+ as M+→M3++2e−,E∘=−0.25V. Under standard conditions, the number of moles of M+ oxidised when one mole of X is converted to Y is: (F=96500Cmole−1)
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Solution
△rG∘=−193kJ/mol
M+→M3++2e−
△G∘ for above reaction is:
△G∘=−nFE∘
=−2×96500×(−0.25)
=48250J/mol
=48.25kJ/mol
Given X→Y
∴ The number of moles of M+ oxidised from (X→Y). =19348.25=4.