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Question

All the energy released from the reaction XY,rG=193 kJ mol1 is used for oxidising M+ as M+M3++2e,E=0.25 V. Under standard conditions, the number of moles of M+ oxidised when one mole of X is converted to Y is: (F=96500 C mole1)

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Solution

rG=193 kJ/mol
M+M3++2e
G for above reaction is:
G=nFE
=2×96500×(0.25)
=48250 J/mol
=48.25 kJ/mol

Given XY
The number of moles of M+ oxidised from (XY). =19348.25=4.

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