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Bohr's Model of a Hydrogen Atom

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Question

All the following complexes are found to be paramagnetic:

$P : [F e F_{6}]^{3 -}; Q : [C o F_{6}]^{3 -}; R : [V (H_{2} O)_{6}]^{3 +}; S : [T i (H_{2} O)_{6}]^{3 +}$

The correct order of their paramagnetic moment (spin only) is:

A

P > Q > R > S

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B

Q > S > R > P

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C

P = Q = R = S

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D

P > R > Q > S

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Solution

The correct option is A $P > Q > R > S$
The complexes P, Q, R and S contain 5, 4, 2 and 1 unpaired electron respectively. With decrease in the number of unpaired electrons, the magnetic moment also decreases.

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Similar questions

Q. Consider the following complex ions:

P, Q,

R

P = [F e F_{6}]^{3 -}, Q = [V (H_{2} O)_{6}]^{2 +}

R = [F e (H_{2} O)_{6}]^{2 +}

The correct order of the complex ions, according to their spin only magnetic moment values (in BM) is:

Q. Consider the following complex ions,

P, Q

R

,

P = [F e F_{6}]^{3 -}, Q = [V (H_{2} O)_{6}]^{2 +}

R = [F e (H_{2} O)_{6}]^{2 +}

.

The correct order of the complex ions, according to their spin-only magnetic moment values (in

B . M .

) is ___________.

Q. Consider the following complex ions P, Q and R.

P = [F e F_{6}]^{3 -}, Q = [V (H_{2} O)_{6}]^{2 +} and R = [F e (H_{2} O)_{6}]^{2 +}

The correct order of the complex ions, according to their spin-only magnetic moment values (in B.M.) is

Q. Consider the following complex ions:

P, Q,

R

P = [F e F_{6}]^{3 -}, Q = [V (H_{2} O)_{6}]^{2 +}

R = [F e (H_{2} O)_{6}]^{2 +}

The correct order of the complex ions, according to their spin only magnetic moment values (in BM) is:

\begin{matrix} Column - 1 & Column - 2 S p e c i e s & C h a r a c t e r i s t i c s (A) C o^{3 +} (Z = 27) & (p) Total number of fully filled orbitals is nine. (B) S c^{3 +} (z = 21) & (q) The value of magnetic moment (spin only) is greater than or equal to 3.87 BM. (C) C r^{3 +} (Z = 24) & (r) Number of electrons with n + l = 3 is eight. (D) N i^{2 +} (Z = 28) & (s) Number of electrons with (m = 0) may be either 11 or 12. (t) No unpaired electron. \end{matrix}

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