Question

All the graphs below are intended to represent the same motion. One of them does it incorrectly. Choose the incorrect one.

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

If velocity versus time graph is a straight line with negative slope, then acceleration is constant and negative.

Then, position-time and distance-time graph will be a parabola facing down given by
$s=ut-\frac{1}{2}a{t}^2$

And since $v^2-u^2=2as$, velocity-position graph will be a parabola symmetric about $x-$ axis.

So, option (b) will be incorrect.