Question

All the graphs below are intended to represent the same motion. One of them does it incorrectly. Pick the incorrect option.

• A.
• B.
• C.
• D.

Answer 1

The correct option is D

If velocity versus time graph is a straight line with negative slope, then acceleration is constant and negative.
With a negative slope, distance-time graph will be parabolic $(s=ut-1/2a{t}^2)$
So, option (d) will be incorrect.