All the letters of the word EAMCET are arranged in all possible ways. The number of such arrangements in which no two vowels are adjacent to each other is
A
360
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B
144
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C
72
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D
54
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Solution
The correct option is B72 Gap method, Consonants M, C, T in 3! = 6 ways and 4 gaps and 3 vowels (2 alike) in 4P312!=12 ways. 12×6=72.