Question

All the particles thrown with the same initial velocity would strike the ground.

• A. With the same speed
• B. Simultaneously.
• C. Time would be least for the particle thrown with velocity $v$ downward, i.e., particle (1).
• D. Time would be maximum for the particle (2).

Answer 1

Answer: (A), (C), (D)

The correct options are
A With the same speed
C Time would be least for the particle thrown with velocity $v$ downward, i.e., particle (1).
D Time would be maximum for the particle (2).

Mechanical energy will be conserved in all cases.
In all situation K.E. (i.e., speed) at the ground are equal.
i.e., option a. is correct.
$h=v{t}_1+\frac{1}{2}g{t}_1^2$ [for (first) particle] (i)
$h=v{t}_2-\frac{1}{2}g{t}_2^2$ [for (second) particle] (ii)
From equation (i) and equation (ii) $t_2>t_1\left(t_2\right)$ = maximum , $\left(t_1\right)$ = minimum
i.e., option (c) and (d) are correct.