All the permutations of the letters of the word $A G A I N$ are arranged as in dictionary, then the fiftieth word is

N A A I G

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A A N I G

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I G N A A

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G A N I A

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Solution

The correct option is D $N A A I G$
Number of words starting with A = $4! = 24$
Starting with G = $12$
Starting with I = $12$
$12 + 12 + 12 + 12 = 48$
NAAGI is $49^{t h}$ word
NAAIG is $50^{t h}$ word of dictionary
Hence, option 'A' is correct.

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