The correct option is D Parabola
y2=4a[x+asin(xa)] ..... (i)
∴2ydydx=4a[1+cos(xa)] ..... (ii)
If tangent is parallel to x-axis, then
dydx=0
So, from Eq. (i), we get
cos(xa)=−1
∴sin(xa)=0
On putting this value in Eq. (i), we get
y2=4a(x+0)⇒y2=4ax
which is parabola.